A circuit with a resistance of $3 Omega$ has a fuse with a capacity of $2 A$ . Can a voltage of $2 V$ be applied to the circuit without blowing the fuse?

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Answer 1 · 2018-03-04T20:22:35

yes

$V = IR$

voltage = current * resistance

here, $R = 3Omega$

and $V = 2V$

$I = V/R = (2V)/(3Omega)$

$I = 2/3A$

when a voltage of $2V$ is applied, the current is $2/3A$ .

a fuse blows when the current goes beyond a certain level.

if the capacity of the fuse is $2A$ , the fuse will blow at any current higher than $2A$ .

$2/3 A < 2A$

there is not enough current for the fuse to blow.

a voltage of $2V$ can be applied without blowing the fuse.

A circuit with a resistance of 3 Omega3 Omega has a fuse with a capacity of 2 A2 A. Can a voltage of 2 V2 V be applied to the circuit without blowing the fuse?