A chemist has one solution that is 50% acid. She has another solution that is 25% acid. How many liters of each type of acid solution should she combine to get 10 liters of 40% acid solution?

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A chemist has one solution that is 50% acid. She has another solution that is 25% acid. How many liters of each type of acid solution should she combine to get 10 liters of 40% acid solution?

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Answer 1 · 2018-08-08T12:58:38

Mixture

Explanation:

n liters from $50 %$ $50%$ acid solution and $10 - n$ $10-n$ liters from $25 %$ $25%$ acid solution to produce 10 liters of 40% acid solution.

$(n \times 0.50) + ((10 - n) \times 0.25) = 10 \times 0.40$ $(ntimes0.50) + ((10-n)times0.25) = 10times0.40$

$0.50 n + 2.5 - 0.25 n = 4$ $0.50n + 2.5 - 0.25n = 4$

$0.25 n = 4 - 2.5$ $0.25n = 4-2.5$

$0.25 n = 1.5$ $0.25n = 1.5$

$n = 6$ $n=6$ liters from $50 %$ $50%$ acid solution.

Take 6 liters from $50 %$ $50%$ acid solution and 4 liters from $25 %$ $25%$ acid solution. The final mixture will be 10 liters and $40 %$ $40%$ acid solution.

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A chemist has one solution that is 50% acid. She has another solution that is 25% acid. How many liters of each type of acid solution should she combine to get 10 liters of 40% acid solution?

1 Answer

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