A charge of #4 C# is passing through points A and B on a circuit. If the charge's electric potential changes from #25 J# to #15 J#, what is the voltage between points A and B?

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Answer 1 · 2017-09-04T16:30:02

The voltage is #=2.5V#

The charge is #Q=It#

We apply Ohm's Law

#U=RI#

The power is

#P=UI#

And the energy is

#E=UIt#

#E=UQ#

and

#DeltaE=QDeltaU#

The voltage is

#DeltaU=(DeltaE)/Q=(25-15)/4=10/4=2.5V#