A bottle of calcium bromide contains a bromide ion concentration of 0.10 mol/L. What is the concentration of the calcium bromide?

1 Answer
anor277
May 30, 2017

[CaBr_2]=0.050*mol*L^-1[CaBr2]=0.050⋅mol⋅L−1

Explanation:

Calcium bromide speciates in aqueous solution according to the following equation.........

CaBr_2(s) stackrel(H_2O)rarrCa^(2+) + 2Br^-CaBr2(s)H2O−−→Ca2++2Br−

And thus for every metal ion there are necessarily two bromide ions.

Here by specification,

[Br^-]=0.10*mol*L^-1[Br−]=0.10⋅mol⋅L−1, and thus [Ca^(2+)]=1/2xx[Br^-]=1/2xx0.10*mol*L^-1=0.050*mol*L^-1[Ca2+]=12×[Br−]=12×0.10⋅mol⋅L−1=0.050⋅mol⋅L−1

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