A 2% solution of sulfuric acid was mixed with a 12% solution of sulfuric acid to produce an 8% solution. How do you determine how much 2% solution and how much 12% solution were used to produce 10 gallons of 8% solution?

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Answer 1 · 2016-04-28T16:49:07

The amount of higher concentration used is $60 %$ $60%$
The amount of lower concentration used is $40 %$ $40%$

There is a trick to this that I discovered when my job was blending of different concentrations.
Tony B Tony B

Let the % amount of higher concentration be $x$ $x$

Then by ratio

$\frac{12 - 2}{100} = \frac{8 - 2}{x}$ $(12-2)/100=(8-2)/x$

$\Rightarrow \frac{x}{6} = \frac{100}{10}$ $=>x/6=100/10$

$\Rightarrow x = 6 \times 10 = 60 %$ $=>x=6xx10=60%$
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Check:

$(\frac{60}{100} \times 12) + (\frac{40}{100} \times 2) = 8$ $(60/100xx12)+(40/100xx2) =8" "$ as required