A #2.3# x #10^-4# #M# solution has trasmittance of #0.508# when placed in a cell of path length #1# #cm# at wavelength #525# #nm#. Calculate the absorbance if concentration is doubled?

1 Answer
anor277
Oct 12, 2016

The absorbance should be #1.160#, or thereabouts.

Explanation:

The #"Beer Lambert Law"#, holds that #A=epsilonbC#, where #epsilon="molar absorptivity"#; #b="cell path length"; and c="concentration in mol L"^-1#.

So if we double the concentration, (or double the path length), we should in principle, double the absorbance. In practice, it is never this easy to do and deviations are common. The #"Beer Lambert Law"# only approximately holds at low concentrations, #~=0.1*mol*L^-1# or lower.

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