A 0.500 L solution of 6 M HCl has to be made. How much 12 M HCI is needed?

1 Answer
May 20, 2017

We use the relationship, concentration=moles of solutevolume of solution TWICE to get a volume of ..............0.25L

Explanation:

concentration=moles of solutevolume of solution

And thus moles of solute=6molL1×0.500L=3mol required initially.

Since this comes from a volume of 12molL1 HCl.....we get

3mol12molL1=0.251L=0.25L

The concentrated hydrochloric acid used in the lab (36%w/w) is 10.6molL1 so this is another poor question.