#6 = sqrt( 2z - 3) - 3? #solve the equation

1 Answer
salamat
Apr 11, 2017

#z = 42#

Explanation:

Assuming your question is #6 = sqrt(2 z -3) -3#

add #3# to both sides
#6 + 3= sqrt(2 z -3) -3 + 3#
#9= sqrt(2 z -3) #

square to both sides
#9^2= (sqrt(2 z -3))^2 #
#81 = 2 z - 3#

add #3# to both sides
#81 + 3= 2 z - 3 + 3#
#84 = 2 z#

divide #2# to both sides
#84/2 = (2 z) /2#

#42 = z#

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