Here Solute is #NaCl#(s) and solution is the #NaCl#(aq)
So, here we have to make #1 Litre# of #4M# #NaCl# solution.
#rArr# Molarity of #NaCl# solution #=# #4M#
and,
Volume of the #NaCl# solution #=# #1 L#
The Molar mass of #NaCl# = #58.44# g/mol
Using the formula of Molarity here we get :-
Molarity of #NaCl# solution #=# (Number of moles of #NaCl#)
/ (Volume of the #NaCl# solution in Litre)
#rArr# #4M# #=# (Number of moles of #NaCl#)/#1L#
#rArr# #4M#x#1L# #=# Number of moles of #NaCl#
#:.# Number of moles of #NaCl# #=# #4# moles
Amount of #NaCl# needed #=# #4# moles x # 58.44#g/mol
#rArr#Amount of #NaCl# needed#=233.76#g#=0.233#kg
