What is the general solution of the differential equation? : dy/dx = 1/x^2
1 Answer
Feb 7, 2018
y =-1/x + C
Explanation:
We have:
dy/dx = 1/x^2
This is a First Order Separable Ordinary Differential Equation. We can "separate the variables" to get:
int \ dy = int \ 1/x^2 \ dx
Both integrals are standard calculus results , so integrating we get:
y = x^(-1)/(-1) + C
\ \ = -1/x + C
Which is the General Solution