Question #0c317

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Answer 1 · 2017-11-13T23:52:14

#1/ (sin(x)cos(x))#

Remember the trigonometric identities

So

#cot(x)sec^2(x)#

#=cot(x)[tan^2(x) + 1]#

#=tan(x) + cot(x)#

#=(sin(x)/cos(x)) + (cos(x)/sin(x))#

#=(sin^2(x)/(sin(x)cos(x))) + (cos^2(x)/(sin(x)cos(x)))#

#=(sin^2(x) + cos^2(x))/ (sin(x)cos(x))#

#=1/(sin(x)cos(x))#