Question #42208

1 Answer
Stefan V.
Nov 5, 2017

"619 g"

Explanation:

The idea here is that we use the percent concentration by mass to show the number of grams of solute present for every "100 g" of a given solution.

In this case, you have a solution that is 2.23 color(blue)(%) by mass silver nitrate, "AgNO"_3, so you can say that this solution will contain "2.23 g" of silver nitrate, the solute, for every color(blue)("100 g") of the solution.

2.23 color(blue)(%)color(white)(.)"AgNO"_3 " "implies" " "2.23 g AgNO"_3 color(white)(.)"per"color(white)(.)color(blue)("100 g")color(white)(.)"of solution"

So all you have to do here is to use the percent concentration of the solution as a conversion factor to find the mass of this solution that would contain "13.8 g" of solute.

13.8 color(red)(cancel(color(black)("g AgNO"_3))) * "100 g solution"/(2.23 color(red)(cancel(color(black)("g AgNO"_3)))) = color(darkgreen)(ul(color(black)("619 g solution")))

The answer is rounded to three sig figs.

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