Question #1a422

1 Answer
Alan P.
Oct 18, 2017

#(12a^(-2)bc^(-2))/(3a^3b^(-3))=color(red)((4b^4)/(a^5c^2))#

Explanation:

Remember that #color(blue)(b^(-a)=1/(b^a))# and #color(blue)(1/b^(-a)=b^a)#

#(12a^(-2)bc^(-2))/(3a^3b^(-3)# can be decomposed as:
#color(white)("XXX")12 * a^(-2) * b * c^(-2) * 1/3 * 1/(a^3) * 1/(b^(-3))#

Using our remembrance
#color(white)("XXX")=12 * 1/(a^2) * b * 1/(c^2) * 1/3 * 1/(a^3) * b^3#

Grouping like factors:
#color(white)("XXX")=underbrace(12 * 1/3) * underbrace(1/(a^2) * 1/(a^3)) * underbrace(b * b^3) * underbrace(1/(c^2))#

Combining like factors:
#color(white)("XXX")=4 * 1/(a^5) * b^4 * 1/(c^2)#

Writing in "compressed form"
#color(white)("XXX")=(4b^4)/(a^5c^2)#

Related questions
See all questions in Negative Exponents
Impact of this question
1178 views around the world
You can reuse this answer
Creative Commons License