What mass of salt is contained in a $200mL$ volume of solution that is $0.10mol*L^-1$ with respect to $KCl(aq)$ ?

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Answer 1 · 2017-09-11T07:48:38

Approx. $1.5*g$ with respect to the salt.....

By definition, $"concentration"="quantity of stuff (mole or grams)"/"volume of solution"$

We have $200*mL$ volume of $KCl(aq)$ that is $0.1*mol*L^-1$ with respect to potassium chloride.....

And so we take the product, and remember that $1*mL-=1xx10^-3*L$ , and so.....

$200*cancel(mL)xx0.10*mol*cancel(L^-1)xx10^-3*cancelL*cancel(mL^-1)=$

$=20.0xx10^-3*mol$

But potassium chloride has a molar mass of $74.55*g*mol^-1$

And so we got a mass of.....

$20.0xx10^-3*molxx74.55*g*mol^-1=??*g$

What mass of salt is contained in a 200*mL200*mL volume of solution that is 0.10*mol*L^-10.10*mol*L^-1 with respect to KCl(aq)KCl(aq)?