The combustion of glucose "C"_6"H"_12"O"_6 produces carbon dioxide and water. What mass of glucose will produce 44 g of carbon dioxide?

1 Answer
Ernest Z.
Sep 5, 2017

The mass of glucose required is 30 g.

Step 1. Start with the balanced equation

M_text(r):color(white)(ml) 180.16color(white)(mmmmmmmmmml)44.01
color(white)(mmm)"C"_6"H"_12"O"_6 + "6O"_2 → "6CO"_2 + 6"H"_2"O""

Step 2. Calculate the moles of "CO"_2"

"Moles of CO"_2 = 44 color(red)(cancel(color(black)("g CO"_2))) × ("1 mol CO"_2)/(44.01color(red)(cancel(color(black)("g CO"_2)))) = "1.00 mol CO"_2"

Step 3. Calculate the moles of "C"_6"H"_12"O"_6

"Moles of C"_6"H"_12"O"_6 = 1.00 color(red)(cancel(color(black)("mol CO"_2))) × (1 "mol C"_6"H"_12"O"_6)/(6color(red)(cancel(color(black)("mol CO"_2)))) = "0.167 mol C"_6"H"_12"O"_6

Step 4. Calculate the mass of "C"_6"H"_12"O"_6

"Mass of C"_6"H"_12"O"_6 = 0.167 color(red)(cancel(color(black)("mol C"_6"H"_12"O"_6))) × ("180.16 g C"_6"H"_12"O"_6)/(1 color(red)(cancel(color(black)("mol C"_6"H"_12"O"_6)))) = "30 g C"_6"H"_12"O"_6

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