The combustion of glucose #"C"_6"H"_12"O"_6# produces carbon dioxide and water. What mass of glucose will produce 44 g of carbon dioxide?

1 Answer
Ernest Z.
Sep 5, 2017

The mass of glucose required is 30 g.

Step 1. Start with the balanced equation

#M_text(r):color(white)(ml) 180.16color(white)(mmmmmmmmmml)44.01#
#color(white)(mmm)"C"_6"H"_12"O"_6 + "6O"_2 → "6CO"_2 + 6"H"_2"O""#

Step 2. Calculate the moles of #"CO"_2"#

#"Moles of CO"_2 = 44 color(red)(cancel(color(black)("g CO"_2))) × ("1 mol CO"_2)/(44.01color(red)(cancel(color(black)("g CO"_2)))) = "1.00 mol CO"_2"#

Step 3. Calculate the moles of #"C"_6"H"_12"O"_6#

#"Moles of C"_6"H"_12"O"_6 = 1.00 color(red)(cancel(color(black)("mol CO"_2))) × (1 "mol C"_6"H"_12"O"_6)/(6color(red)(cancel(color(black)("mol CO"_2)))) = "0.167 mol C"_6"H"_12"O"_6#

Step 4. Calculate the mass of #"C"_6"H"_12"O"_6#

#"Mass of C"_6"H"_12"O"_6 = 0.167 color(red)(cancel(color(black)("mol C"_6"H"_12"O"_6))) × ("180.16 g C"_6"H"_12"O"_6)/(1 color(red)(cancel(color(black)("mol C"_6"H"_12"O"_6)))) = "30 g C"_6"H"_12"O"_6#

Related questions
See all questions in Stoichiometry
Impact of this question
2246 views around the world
You can reuse this answer
Creative Commons License