How would the volume if a gas in a piston under #14"bar"# pressure with a volume of #312mL#, were reduced in pressure to #7*"bar"# pressure?

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Answer 1 · 2017-09-04T14:30:50

Would it not be around #7*"bar"#.........?

Old Boyle's Law holds that given constant temperature, and for a given amount of gas.....#Pprop1/V#........

Else, #PV=k#, and thus solving for #k# at different pressures and volumes......

#P_1V_1=P_2V_2#

And so......#P_2=(P_1V_1)/V_2=(14*"bar"xx312*mL)/(652*mL)=??*"bar"#.

How would the volume if a gas in a piston under #14*"bar"# pressure with a volume of #312*mL#, were reduced in pressure to #7*"bar"# pressure?