If the molar mass of a material is #147.01gmol^-1#, what mass of the material is required for a #1L# volume of a #0.1mol*L^-1# solution?

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Answer 1 · 2017-08-29T19:27:14

We use the definition of concentration......#"Concentration"="Moles"/"Volume"#.

And we get a required mass of #14.7*g#.

And thus #"moles"="volume"xx"concentration"#

We require.....#1*Lxx0.1*mol*L^-1=0.1*mol#.

And now we simply multiply this molar quantity by the molar mass, i.e. #0.1*molxx147.01*g*mol^-1=14.7*g#.....

If the molar mass of a material is #147.01*g*mol^-1#, what mass of the material is required for a #1*L# volume of a #0.1*mol*L^-1# solution?