What is the concentration in #"ppm"# if #18.5g# of solute are dissolved in a #125L# volume?

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Answer 1 · 2017-08-28T15:01:29

Well #1*"ppm"# #=# #1*mg*L^-1#.......

And so we set up the quotient, #"milligrams of solute"/"litres of water"#

#=(18.5*gxx10^3*mg*g^-1)/(125000*gxx10^-3*L*g^-1)=148.0*"ppm"#

What is the concentration in #"ppm"# if #18.5*g# of solute are dissolved in a #125*L# volume?