The pressure on a #22.5L# volume of gas enclosed in a piston is REDUCED from #748mmHg# to #725mm*Hg#. What is the new volume?

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Answer 1 · 2017-08-27T13:09:26

Well, #P_1V_1=P_2V_2#.......and the VOLUME should INCREASE BECAUSE YOU DECREASE the PRESSURE......

And so....#V_2=(P_1V_1)/P_2#, which clearly has the units of volume. Agreed?

#V_2=(22.5*Lxx748*mm*Hg)/(725*mm*Hg)=??*L#

The pressure on a #22.5*L# volume of gas enclosed in a piston is REDUCED from #748*mm*Hg# to #725*mm*Hg#. What is the new volume?