How many angular nodes are in a #d_(z^2)# orbital?

Question

28921 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-08-22T20:01:31

The number of angular nodes in a #"d"_text(z²)# orbital is two.

For any orbital,

#"Total no. of nodes" = n - 1#

#"No. of angular nodes" = l#

#"No. of radial nodes" = n - l - 1#

It is easy to see the two angular (conical) nodes in a #3"d"_text(z²)# orbital.

www.dartmouth.edu

A #4"d"_text(z²)# orbital has the same two conical nodes plus a radial (spherical) node.

4dz2
(From Roland Heynkes)

A #5"d"_text(z²)# orbital has the same two conical nodes plus two radial (spherical) nodes.