How many angular nodes are in a $d_(z^2)$ orbital?

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Answer 1 · 2017-08-22T20:01:31

The number of angular nodes in a $"d"_text(z²)$ orbital is two.

For any orbital,

$"Total no. of nodes" = n - 1$

$"No. of angular nodes" = l$

$"No. of radial nodes" = n - l - 1$

It is easy to see the two angular (conical) nodes in a $3"d"_text(z²)$ orbital.

www.dartmouth.edu

A $4"d"_text(z²)$ orbital has the same two conical nodes plus a radial (spherical) node.

4dz2
(From Roland Heynkes)

A $5"d"_text(z²)$ orbital has the same two conical nodes plus two radial (spherical) nodes.

How many angular nodes are in a d_(z^2)d_(z^2) orbital?