What is the molar concentration of #"38% w/w HCl"#?

1 Answer
anor277
Aug 12, 2017

#"Concentration HCl"=12.7*mol*L^-1#

Explanation:

How did I get that figure? Well we need a value for the density of #HCl#; this site reports that the density of #38%# #HCl# is #rho=1.189*g*mL#. Now we need this value if we are to approach the question......

#"Concentration"="Molarity"="Moles of solute (mol)"/"Volume of solution (L)"#

And thus.....#"molarity"# using a volume of #1*mL#....

#=((38%xx1.189*g*mL^-1xx1*mL)/(35.45*g*mol^-1))/(1xx10^-3*L)=12.7*mol*L^-1#.

Related questions
See all questions in Molarity
Impact of this question
3748 views around the world
You can reuse this answer
Creative Commons License