What is the concentration of a $40g$ mass of sodium hydroxide dissolved in $250mL$ of water?

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Answer 1 · 2017-07-30T04:46:57

Approx. $4*mol*L^-1$ .......or $4.0*"normal"$

$[NaOH]=((40*g)/(40*g*mol^-1))/(250xx10^3*mLxx10^-3*L*mL^-1)=4.0*mol*L^-1$

This follows the normal means of calculation, $"concentration"="moles of solute"/"volume of solution"$ , and thus get an answer in $mol*L^-1$ .

We assume no volume change on dissolution.

And under these circumstances, where the solute causes no further water hydrolysis, $"molarity "-=" normality"$ ...........

What is the concentration of a 40*g40*g mass of sodium hydroxide dissolved in 250*mL250*mL of water?