What is the concentration of a #40g# mass of sodium hydroxide dissolved in #250mL# of water?

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Answer 1 · 2017-07-30T04:46:57

Approx. #4*mol*L^-1#.......or #4.0*"normal"#

#[NaOH]=((40*g)/(40*g*mol^-1))/(250xx10^3*mLxx10^-3*L*mL^-1)=4.0*mol*L^-1#

This follows the normal means of calculation, #"concentration"="moles of solute"/"volume of solution"#, and thus get an answer in #mol*L^-1#.

We assume no volume change on dissolution.

And under these circumstances, where the solute causes no further water hydrolysis, #"molarity "-=" normality"#...........

What is the concentration of a #40*g# mass of sodium hydroxide dissolved in #250*mL# of water?