Question #792b1

1 Answer
Stefan V.
Jul 26, 2017

#"0.83 L"#

Explanation:

Molarity is all about the number of moles of solute and the volume of the solution expressed in liters, so start by using the 8molar mass* of calcium chloride to calculate the number of moles present in your sample.

#212 color(red)(cancel(color(black)("g"))) * "1 mole CaCl"_2/(110.98color(red)(cancel(color(black)("g")))) = "1.91 moles CaCl"_2#

Now, you know that in order to have a #"2.3-M"# solution of calcium chloride, you need to have #2.3# moles of calcium chloride for every #"1 L"# of solution.

Since solutions are homogeneous mixtures, i.e. they have the same composition throughout, you can use the molarity of the solution as a conversion factor to find the volume of solution that would contain #1.91# moles of solute.

#1.91 color(red)(cancel(color(black)("moles CaCl"_2))) * overbrace("1 L solution"/(2.3color(red)(cancel(color(black)("moles CaCl"_2)))))^(color(blue)("= 2.3 M")) = color(darkgreen)(ul(color(black)("0.83 L solution")))#

The answer is rounded to two sig figs, the number of significant figures you have for the molarity of the solution.

Related questions
See all questions in Molarity
Impact of this question
1746 views around the world
You can reuse this answer
Creative Commons License