What mass of barium chloride is present in a 100*mL of barium chloride solution of 0.250*mol*L^-1 concentration?

1 Answer
Jul 24, 2017

Well, by definition, "Concentration"="Moles of stuff"/"Volume of solution". I gets a mass of approx. 5*g.

Explanation:

And thus, "moles of stuff"="concentration"xx"volume of solution".

And in turn, "moles of stuff"="Mass of stuff"/"Molar mass of stuff".

We have a 100*cm^3 volume of a 0.250*mol*L^-1 solution of BaCl_2. And 1*cm^3=1*mL=10^-3*L.

And so ................."moles of barium chloride"=100xx10^-3*cancelLxx0.250*mol*cancel(L^-1)

-=100xx10^-3xx0.250*mol-=0.0250*mol.

The molar mass of barium chloride is 208.23*g*mol^-1.

And thus "mass"=0.0250*molxx208.23*g*mol^-1=??*g.