How would the volume evolve if a #13000*L# of gas under a #1.38*atm# pressure were subjected to a #250*atm# pressure?

1 Answer
anor277
Jul 21, 2017

The new volume would have to be smaller.........

Explanation:

We use old Boyle's law, which holds that #Pprop1/V#

And thus #P=k/V#, where #k# is some constant.......and if we solve for #k# under different conditions of pressure and volume (but constant temperature), then..........

#P_1V_1=P_2V_2#....

And thus #V_2=(P_1V_1)/P_2=(1.38*atmxx13000*L)/(250*atm)#

#71.76*L#.

As regards the experimental setup, the experiment would have to be performed in a huge piston..... Perhaps the apparatus is not physically reasonable.

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