How much dihydrogen would evolve if sodium metal were dropped into water?

1 Answer
anor277
Jul 18, 2017

You need to specify a mass of sodium metal.......

Na(s) + H_2O(l) rarr NaOH(aq) + 1/2H_2(g)uarr

Explanation:

If 1*g of sodium metal were dropped into a beaker of water, along with spitz and sparx we would get......

1/2xx(1*g)/(22.99*g*mol^-1)xx2.02*g*mol^-1=0.044*g "dihydrogen gas".

Of course, if we specify the temperature, and assume 1*atm pressure, we could calculate the volume of dihydrogen gas produced.

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