Question #b1009

1 Answer
anor277
Jul 14, 2017

#"Molarity"="Moles of acid"/"Volume of soltion."#

And by the way you add acid to water, and never water to acid..

Explanation:

We have a molar quantity of ..........................

#7.2*mol*L^-1xx455.2*mLxx10^-3*L*mL^-1=3.28*mol# with respect to #HCl#.

And thus.............. #"Molarity"=(7.2*mol*L^-1xx455.2*mLxx10^-3*L*mL^-1)/(1270.0*L)#

#=2.258xx10^-3*mol*L^-1#

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