Question #b1009

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Question #b1009

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Answer 1 · 2017-07-14T20:30:20

$Molarity = \frac{Moles of acid}{Volume of soltion.}$ $"Molarity"="Moles of acid"/"Volume of soltion."$

And by the way you add acid to water, and never water to acid..

Explanation:

We have a molar quantity of ..........................

$7.2 \cdot m o l \cdot L^{- 1} \times 455.2 \cdot m L \times 10^{- 3} \cdot L \cdot m L^{- 1} = 3.28 \cdot m o l$ $7.2*mol*L^-1xx455.2*mLxx10^-3*L*mL^-1=3.28*mol$ with respect to $H C l$ $HCl$ .

And thus.............. $Molarity = \frac{7.2 \cdot m o l \cdot L^{- 1} \times 455.2 \cdot m L \times 10^{- 3} \cdot L \cdot m L^{- 1}}{1270.0 \cdot L}$ $"Molarity"=(7.2*mol*L^-1xx455.2*mLxx10^-3*L*mL^-1)/(1270.0*L)$

$= 2.258 \times 10^{- 3} \cdot m o l \cdot L^{- 1}$ $=2.258xx10^-3*mol*L^-1$

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Question #b1009

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