What is the molar concentration of a $2 % (\frac{weight}{volume})$ $2%("weight"/"volume")$ solution of sodium hydroxide?

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What is the molar concentration of a $2 % (\frac{weight}{volume})$ $2%("weight"/"volume")$ solution of sodium hydroxide?

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Answer 1 · 2017-06-29T06:03:44

We assume that we deal with a $2 %$ $2%$ $\frac{weight}{volume}$ $"weight"/"volume"$ solution......

Explanation:

That is $2 \cdot g$ $2*g$ of $sodium hydroxide$ $"sodium hydroxide"$ are dissolved in a $100 \cdot m L$ $100*mL$ volume of water........

$Concentration = \frac{Moles of solute}{Volume of solution}$ $"Concentration"="Moles of solute"/"Volume of solution"$

$= \frac{\frac{2.0 \cdot g}{39.99 \cdot g \cdot m o l^{- 1}}}{100 \cdot m L \times 10^{- 3} \cdot L \cdot m L^{- 1}} = 0.500 \cdot m o l \cdot L^{- 1}$ $=((2.0*g)/(39.99*g*mol^-1))/(100*mLxx10^-3*L*mL^-1)=0.500*mol*L^-1$

Please note my assumption.......in questions of this kind normally the density of the solution would also be quoted.

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What is the molar concentration of a $2 % (\frac{weight}{volume})$ $2%("weight"/"volume")$ solution of sodium hydroxide?

1 Answer

Explanation:

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Science

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What is the molar concentration of a 2%("weight"/"volume")2%(weightvolume)2%("weight"/"volume") solution of sodium hydroxide?

1 Answer

Explanation:

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What is the molar concentration of a $2 % (\frac{weight}{volume})$ $2%("weight"/"volume")$ solution of sodium hydroxide?