Question #b844d

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Doc048
Jun 29, 2017

#(10 mgNO_3)/(Liter)# = #((0.01gNO_3)/(1000g"Soln"))#

In each of the following, note how the ratio (in common units) is multiplied by the factor needed; that is,
=> pph = ratio x 100 => %
=> ppm = ratio x 1-million
=> ppb = ratio x 1-billion

=> #%NO_3# = Parts per Hundred = #((0.01gNO_3)/(1000g"Soln"))# x 100% = #1xx10^-3%(NO_3)# or #1xx10^-3# parts per hundred (pph)

=> Parts per Million #("ppm")# = #((0.01gNO_3)/(1000g"Soln"))# x #10^6("ppm")# = 10 ppm

=> Parts per Billion #("ppb")# = #((0.01gNO_3)/(1000g"Soln"))# x #10^9("ppb")# = 10000 ppb

=> Molarity(M) = #"moles"/"Liter"# = #((0.01gNO_3)/(62(g)/(mol)))(L^-1)# = #1.61xx10^-4M#

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