Given EXCESS zinc metal, what volume of dihydrogen gas at #"NTP"# will be evolved from the action of #500cm^3# of #H_2SO_4# at #0.50mol*L^-1# concentration?

Question

1622 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-24T06:51:28

We interrogate the redox reaction......

#Zn(s) + H_2SO_4(aq) rarr ZnSO_4(aq) + H_2(g)uarr#

And thus ONE equiv of dihydrogen results from each equiv of sulfuric acid (and also from each equiv of zinc metal).........

As far as I know #"NTP"# specifies #1*atm# pressure and #293.15*K#, and the molar volume of an Ideal Gas at #NTP# is #24.05*L#

#"Moles of sulfuric acid"=500*cm^3xx10^-3*L*cm^-3xx0.5*mol*L^-1=0.25*mol#

And thus #0.25*mol# dihydrogen gas will be evolved.

And so volume at #"NTP"=0.25*molxx24.05*L*mol^-1~=6*L#

Given EXCESS zinc metal, what volume of dihydrogen gas at #"NTP"# will be evolved from the action of #500*cm^3# of #H_2SO_4# at #0.50*mol*L^-1# concentration?