Given EXCESS zinc metal, what volume of dihydrogen gas at $NTP$ $"NTP"$ will be evolved from the action of $500 \cdot c m^{3}$ $500cm^3$ of $H_{2} S O_{4}$ $H_2SO_4$ at $0.50 \cdot m o l \cdot L^{- 1}$ $0.50mol*L^-1$ concentration?

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Given EXCESS zinc metal, what volume of dihydrogen gas at $NTP$ $"NTP"$ will be evolved from the action of $500 \cdot c m^{3}$ $500cm^3$ of $H_{2} S O_{4}$ $H_2SO_4$ at $0.50 \cdot m o l \cdot L^{- 1}$ $0.50mol*L^-1$ concentration?

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Answer 1 · 2017-06-24T06:51:28

We interrogate the redox reaction......

$Z n (s) + H_{2} S O_{4} (a q) \to Z n S O_{4} (a q) + H_{2} (g) ↑ ⏐$ $Zn(s) + H_2SO_4(aq) rarr ZnSO_4(aq) + H_2(g)uarr$

Explanation:

And thus ONE equiv of dihydrogen results from each equiv of sulfuric acid (and also from each equiv of zinc metal).........

As far as I know $NTP$ $"NTP"$ specifies $1 \cdot a t m$ $1*atm$ pressure and $293.15 \cdot K$ $293.15*K$ , and the molar volume of an Ideal Gas at $N T P$ $NTP$ is $24.05 \cdot L$ $24.05*L$

$Moles of sulfuric acid = 500 \cdot c m^{3} \times 10^{- 3} \cdot L \cdot c m^{- 3} \times 0.5 \cdot m o l \cdot L^{- 1} = 0.25 \cdot m o l$ $"Moles of sulfuric acid"=500*cm^3xx10^-3*L*cm^-3xx0.5*mol*L^-1=0.25*mol$

And thus $0.25 \cdot m o l$ $0.25*mol$ dihydrogen gas will be evolved.

And so volume at $NTP = 0.25 \cdot m o l \times 24.05 \cdot L \cdot m o l^{- 1} ≅ 6 \cdot L$ $"NTP"=0.25*molxx24.05*L*mol^-1~=6*L$

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Given EXCESS zinc metal, what volume of dihydrogen gas at $NTP$ $"NTP"$ will be evolved from the action of $500 \cdot c m^{3}$ $500cm^3$ of $H_{2} S O_{4}$ $H_2SO_4$ at $0.50 \cdot m o l \cdot L^{- 1}$ $0.50mol*L^-1$ concentration?

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Given EXCESS zinc metal, what volume of dihydrogen gas at "NTP"NTP"NTP" will be evolved from the action of 500*cm^3500⋅cm3500*cm^3 of H_2SO_4H2SO4H_2SO_4 at 0.50*mol*L^-10.50⋅mol⋅L−10.50*mol*L^-1 concentration?

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Given EXCESS zinc metal, what volume of dihydrogen gas at $NTP$ $"NTP"$ will be evolved from the action of $500 \cdot c m^{3}$ $500cm^3$ of $H_{2} S O_{4}$ $H_2SO_4$ at $0.50 \cdot m o l \cdot L^{- 1}$ $0.50mol*L^-1$ concentration?