How many bonds in $H_{3} C - C H = C H - C H_{2} - C H_{3}$ $H_3C-CH=CH-CH_2-CH_3$ ?

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Answer 1 · 2017-08-30T21:45:51

Well, I counts $1 \times π$ $1xxpi$ bond......

And I count $4 \times C - C$ $4xxC-C$ $σ$ $sigma$ bonds.....

And $10 \times C - H$ $10xxC-H$ $σ$ $sigma$ bonds.....And thus there $15$ $15$ $π$ $pi$ and $σ$ $sigma$ bonds in total.

How many bonds in H3C−CH=CH−CH2−CH3H_3C-CH=CH-CH_2-CH_3?