Question #b8733

1 Answer
Jun 24, 2017

In case of acid base neutralization we know the relation

Sa×Va=Sb×Vb

Where

Sastrength of acid solution in Normality=?

VaVolume of acid solution=2mL

Sbstrength of base solution in Normality=N5

VbVolume of acid solution=10mL

Hence

Sa×Va=Sb×Vb

Sa×2=N5×10

Sa=1(N)