Question #b8733

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Answer 1 · 2017-06-24T05:45:30

In case of acid base neutralization we know the relation

$S_axxV_a=S_bxxV_b$

Where

$S_a-> "strength of acid solution in Normality" =?$

$V_a->"Volume of acid solution"=2mL$

$S_b-> "strength of base solution in Normality"=N/5$

$V_b->"Volume of acid solution"=10mL$

Hence

$S_axxV_a=S_bxxV_b$

$=>S_axx2=N/5xx10$

$=>S_a=1(N)$