What $["OH"^(-)]$ and $"pOH"$ give a basic solution?

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Answer 1 · 2017-06-21T13:41:30

A low $["OH"^"-"]$ and a high $"pOH"$ best state the basicity of a solution.

Low $["OH"^"-"]$

Let's say that $["OH"^"-"] = 10^"-10"color(white)(l) "mol/L"$ (low $["OH"^"-"]$ .

Then

$"pOH" = -log["OH"^"-"] = -log10^"-10" = 10$

Thus, a low $["OH"^"-"]$ means a high $"pOH"$ .

High $["OH"^"-"]$

Let's say that $["OH"^"-"] = 10color(white)(l) "mol/L"$ (high $["OH"^"-"])$ .

Then

$"pOH" = -log["OH"^"-"] = -log10^"10" = 1$

Thus, a high $["OH"^"-"]$ means a low $"pOH"$ .

What ["OH"^(-)]["OH"^(-)] and "pOH""pOH" give a basic solution?