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Question #42d80

1 Answer

Jun 20, 2017

1.12 L

Explanation:

#S_8 + 8O_2 => 8SO_2#

=> 1 mole #S_8# => 8 moles #SO_2#

#"moles" S_8 = (1.6 g)/(256 g/"mole") = 0.00625 "mole"#

=> 0.00625 mole #S_8# => 0.00625(8) mole #SO_2# = 0.05 mole #S_8#

=> at STP => 0.05 mole #SO_2# => 0.05 mole ( 22.4 L/mole at STP ) = 1.12 Liters #SO_2#

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