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Answer 1 · 2017-06-21T01:11:03

The percentage of $N-14$ $"N-14"$ is 99.6 %.

The masses of $N-14$ $"N-14"$ and $N-15$ $"N-15"$ are 14.003 u and 15.000 u, respectively.

Let $x$ $x$ be the fraction of $N$ $"N"$ that is $N-14$ $"N-14"$ .

Then $(1 - x)$ $(1-x)$ is the fraction that is N-15.

$14.003x color(red)(cancel(color(black)("u"))) + (1-x) color(red)(cancel(color(black)("u"))) = 14.007 color(red)(cancel(color(black)("u")))$

$14.003 x +15.000 - 15.000x = 14.007$

$0.997x = 0.993$

$x = 0.993/0.997 = 0.996$

∴ Natural nitrogen is 99.6 % $"N-14"$ .