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Answer 1 · 2017-06-21T01:11:03

The percentage of #"N-14"# is 99.6 %.

The masses of #"N-14"# and #"N-15"# are 14.003 u and 15.000 u, respectively.

Let #x# be the fraction of #"N"# that is #"N-14"#.

Then #(1-x)# is the fraction that is N-15.

#14.003x color(red)(cancel(color(black)("u"))) + (1-x) color(red)(cancel(color(black)("u"))) = 14.007 color(red)(cancel(color(black)("u")))#

#14.003 x +15.000 - 15.000x = 14.007#

#0.997x = 0.993#

#x = 0.993/0.997 = 0.996#

∴ Natural nitrogen is 99.6 % #"N-14"#.