Question #17866

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Answer 1 · 2017-06-14T16:07:44

The mixture is 35.7 % $"Mg"^"+"$ and 64.3 % $"Mg"^"2+"$ .

Let $x$ be the fraction of $"Mg"$ that absorbs 750 kJ.

Then (1-x) is the fraction that absorbs 1450 kJ.

$750x + 1450(1-x) = 1200$

$750x + 1450 - 1450x = 1200$

$700x = 250$

$x = 250/700 = 0.357$

∴ The mixture is 35.7 % $"Mg"^"+"$ and 64.3 % $"Mg"^"2+"$ .