Question #31517

Question

1807 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-02T03:23:33

$y = \frac{1}{4} x^{2} + 3$ $y= 1/4 x^2 + 3$

$\frac{d y}{d x} = \frac{1}{2} x$ $(dy)/(dx) = 1/2 x$

$y = \int d y = \int \frac{1}{2} x d x$ $y = int dy = int 1/2 x dx$

$y = \frac{1}{4} x^{2} + c$ $y = 1/4 x^2 + c$

plug in $y = 3, x = 2$ $y = 3, x = 2$ in the above equation to find $c$ $c$

$3 = \frac{1}{4} {(2)}^{2} + c$ $3 =1/4 (2)^2 + c$

$3 = c$ $3 = c$

therefore it equation is $y = \frac{1}{4} x^{2} + 3$ $y= 1/4 x^2 + 3$