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If $y=x^3+2x$ and $dx/dt=5$ , how do you find $dy/dt$ when $x=2$ ?

1 Answer

Sep 21, 2014

By Implicit Differentiation,

${dy}/{dt}=70$

By differentiating with respect to $t$ ,

${dy}/{dt}=d/{dt}(x^3+2x)=(3x^2+2){dx}/{dt}$

by plugging in $x=2$ and ${dx}/{dt}=5$ ,

$=[3(2)^2+2] (5)=70$

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