Question #a9d2d
1 Answer
-
#"H"_2# is limiting -
#"N"_2# is excess -
#1.3# #"mol N"_2# remaining -
#23"g NH"_3# form
Explanation:
We're asked to find (1) the limiting reactant in the reaction, (2) the excess reactant, (3) the number of moles of excess reactant remaining after the reaction goes to completion, and (4) the mass of the ammonia gas formed.
1.
First things first, let's write the chemical equation for this reaction:
To find the limiting reactant, we must first convert the given quantities of reactants to moles, and then divide by the coefficient in front of it. Whichever quantity after that is lower, that reactant is limiting.
To convert the mass of
To find the number of moles of
Now let's divide these numbers by their respective coefficients:
Since the value for
2.
Intuitively, since hydrogen is the limiting reactant,
3.
To find the number of unreacted moles of the excess reactant (
4.
Lastly, we need to find the mass of ammonia formed. We can use the coefficients to find the moles of ammonia, and then use its molar mass to find the mass, in