Question #12ce4

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Answer 1 · 2017-05-26T20:27:28

The new pressure is 19.9 psi.

Given

The pressure (#p_1#) of a gas at a temperature #T_1#.
A second temperature #T_2#.

Find

The second pressure #p_2#.

Strategy

A problem involving two gas pressures and two temperatures must be a Gay-Lussac's Law problem.

Gay-Lussac's Law is

#color(blue)(bar(ul(|color(white)(a/a)p_1/T_1 = p_2/T_2color(white)(a/a)|)))" "#

1. Solve the Gay-Lussac's Law expression for #p_2#.

2. Insert the numbers into the #p_2# expression.

Solution

#p_2 = p_1 × T_2/T_1#

In your problem,

#p_1 = "22.5 psi"; T_1 = "(110 + 273.15K)" = "383.15 K"#
#p_2 = ?; color(white)(mmm)T_2 = "(65 + 273.15 K)" = "338.15 K"#

#p_2 = "22.5 psi" × (338.15 cancel("K"))/(383.15 cancel("K")) = "19.9 psi"#