What is the molarity of a $0.28mol$ quantity confined to a volume of $2.6L$ ?

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Answer 1 · 2017-05-25T06:47:32

$"Molarity"="Moles of solute"/"Volume of soluton"..............$

And thus...........

$"Molarity"=(0.28*mol)/(2.6*L)=0.108*mol*L^-1............$

The quotient gives us the required units of concentration.....

$"moles of solute per volume of solution"$ , i.e. $mol*L^-1$ .

What is the molarity of a 0.28*mol0.28*mol quantity confined to a volume of 2.6*L2.6*L?