What are the valence electrons in #MgCl^+#, #CO_2#, and #HF#?

1 Answer
anor277
May 23, 2017

Well magnesium is an #"alkaline earth"#, i.e. a #"Group 2 metal cation"#....

Explanation:

And so for #MgCl^+#; you possibly meant to write #MgCl_2#, i.e. #Mg^(2+) + 2xxCl^-#.

For #CO_2#, we have #4+6+6# valence electrons to distribute; i.e. 8 electron pairs:

#:stackrel(..)O=C=stackrel(..)O:#

And for hydrogen fluoride, we have #1+7# valence electrons, i.e. 4 electron pairs...........

#H-F#.

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