Question #40a6a

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Question #40a6a

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Answer 1 · 2017-05-20T18:38:09

256 milligrams

Explanation:

If we convert 64kg to milligrams, there is 64, 000, 000 mg of person (a funny concept!) as there are 1 million milligrams in a kilogram.
So, if there are four parts for each million, and there are 64 million grams, then there will be $64 \times 4 = 256$ $64xx4=256$ milligrams

Hope this helps; let me know if I can do anything else:)

Answer 2 · 2017-05-20T18:41:05

$256.00$ $256.00$ $mg$ $"mg"$

Explanation:

The average concentration of $PCB$ $"PCB"$ s in the body tissue of a human is $4.00$ $4.00$ $ppm$ $"ppm"$ .

Let's convert the units of the concentration from $ppm$ $"ppm"$ to $mg$ $"mg"$ / $kg$ $"kg"$ :

$\Rightarrow 1$ $⇒ 1$ $ppm$ $"ppm"$ $= 1$ $= 1$ $mg$ $"mg"$ / $kg$ $"kg"$

$\Rightarrow 4.00$ $⇒ 4.00$ $ppm$ $"ppm"$ $= 4.00$ $= 4.00$ $mg$ $"mg"$ / $kg$ $"kg"$

We need to find the mass of $PCB$ $"PCB"$ s found in a $64$ $64$ $kg$ $"kg"$ human.

So let's set up a ratio using this information:

$\Rightarrow \frac{4.00 mg}{1 kg} = \frac{x}{64 kg}$ $⇒ frac(4.00 " mg")(1 " kg") = frac(x)(64 " kg")$

Multiply both sides by $64$ $64$ $kg$ $"kg"$ :

$\Rightarrow \frac{4.00 mg \times 64 kg}{1 kg} = \frac{x \times 64 kg}{64 kg}$ $⇒ frac(4.00 " mg" × 64 " kg")(1 " kg") = frac(x × 64 " kg")(64 " kg")$

$\Rightarrow 256.00$ $⇒ 256.00$ $mg$ $"mg"$ $= x$ $= x$

$∴ x = 256.00$ $"mg"$

Therefore, the mass of $"PCB"$ s present in a $64$ $"kg"$ person's body is $256.00$ $"mg"$ .

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