Question #a939a

1 Answer
May 20, 2017

"26% NaCl"26% NaCl

Explanation:

The problem wants you to calculate the percent concentration by mass, "% m/m"% m/m, of sodium chloride in this solution.

The key thing to remember here is that a solution's percent concentration by mass tells you the mass of solute, which in your case is sodium chloride, present for every "100 g"100 g of solution.

After you dissolve the sodium chloride, the mass of the solution will be

m_"solution" = "36 g" + "100 g" = "136 g"msolution=36 g+100 g=136 g

You know that you have "36 g"36 g of sodium chloride in "136 g"136 g, so use this as a conversion factor to find the mass of sodium chloride present in "100 g"100 g of solution

100 color(red)(cancel(color(black)("g solution"))) * "36 g NaCl"/(136color(red)(cancel(color(black)("g solution")))) = "26.47 g NaCl"

This means that the solution's percent concentration by mass is

color(darkgreen)(ul(color(black)("% NaCl" = 26%)))

The answer is rounded to two sig figs.