Question #50b52

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Question #50b52

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Answer 1 · 2017-05-19T15:47:27

Farmer's Speed $=10/40=0.25ms^-1$

Let the farmer be at the origin initially.
Total time of travel $=60xx2+20=120+20=140sec$
Total distance traveled $=0.25xx140=35m$

Field being square of side $=10m$
$:.$ Total number of sides traveled in the given time $=3.5$

We know that after traveling $4$ sides farmer would be back at the origin.
As such magnitude of displacement after given time $=4-3.5=1/2 side$
$=1/2xx10=5m$

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