A 45.33*mL45.33⋅mL volume of Sr(OH)_2(aq)Sr(OH)2(aq) was titrated with a 19.81*mL19.81⋅mL volume of 0.44*mol*L^-10.44⋅mol⋅L−1 concentration. What is [Sr(OH)_2][Sr(OH)2]?

1 Answer
anor277
May 18, 2017

[Sr(OH)_2]~=0.1*moL^-1[Sr(OH)2]≅0.1⋅moL−1

Explanation:

We assess the stoichiometric reaction:

Sr(OH)_2(s) +2HCl(aq) rarr SrCl_2(aq) + 2H_2O(l)Sr(OH)2(s)+2HCl(aq)→SrCl2(aq)+2H2O(l)

"Moles of HCl"-=19.81*mLxx10^-3*L*mL^-1xx0.44*mol*L^-1=8.72xx10^-3*molMoles of HCl≡19.81⋅mL×10−3⋅L⋅mL−1×0.44⋅mol⋅L−1=8.72×10−3⋅mol.

And thus there were (8.72xx10^-3*mol)/28.72×10−3⋅mol2 WITH RESPECT TO Sr(OH)_2Sr(OH)2

[Sr(OH)_2]=((8.72xx10^-3*mol)/2)/(45.33xx10^-3*L)=0.0961*mol*L^-1[Sr(OH)2]=8.72×10−3⋅mol245.33×10−3⋅L=0.0961⋅mol⋅L−1.

I don't think this problem is too realistic because I doubt that you could prepare a Sr(OH)_2Sr(OH)2 solution this concentrated.

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