Question #eb759

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Question #eb759

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Answer 1 · 2017-05-12T18:56:16

$Option D.....$ $"Option D....."$

Explanation:

$Molarity = \frac{Moles of solute}{Volume of solution}$ $"Molarity"="Moles of solute"/"Volume of solution"$ , and thus has units of $m o l \cdot L^{- 1}$ $mol*L^-1$ .

And in $1 \cdot L$ $1*L$ of $3.5 \cdot m o l \cdot L^{- 1}$ $3.5*mol*L^-1$ $K N O_{3}$ $KNO_3$ , there are.......................

$1 \cdot L \times 3.5 \cdot m o l \cdot L^{- 1} = 3.5 \cdot m o l$ $1*Lxx3.5*mol*L^-1=3.5*mol$ solute............with respect to $potassium nitrate$ $"potassium nitrate"$ .

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