Question #81c72

1 Answer
May 14, 2017

Yes, the reaction is spontaneous.

Explanation:

We can answer this question by examining the standard reduction potentials for the half-reactions.

color(white)(mmmmmmmmmmmmmmmmmmmmmmmmmmmml) E^@"/V"mmmmmmmmmmmmmmmmmmmmmmmmmmmmlE/V
2×["MnO"_4^"-" + 8"H"^"+" + 5"e"^"-" → "Mn"^"2+" + 4"H"_2"O"]; color(white)(mmmmmml)"+1.51"2×[MnO-4+8H++5e-Mn2++4H2O];mmmmmml+1.51
5×["H"_2"C"_2"O"_4 → "2CO"_2 + "2H"^"+" + "2e"^"-"]; color(white)(mmmmmmmmmll)"+0.49"5×[H2C2O42CO2+2H++2e-];mmmmmmmmmll+0.49
2"MnO"_4^"-" + 5"H"_2"C"_2"O"_4 +"6H"^"+" → 2"Mn"^"2+" + 10"CO"_2 +8"H"_2"O"; "+2.00"2MnO-4+5H2C2O4+6H+2Mn2++10CO2+8H2O;+2.00

The condition for spontaneity is that ΔG < 0.

ΔG^@ = -nFE^@

Since E^@ > 0, ΔG^@ < 0, and the reaction is spontaneous.