What is $[H_3O^+]$ in an aqueous solution whose $pOH=8.26$ ?

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Answer 1 · 2017-05-06T18:20:05

By definition $pOH=-log_(10)[HO^-]$ ..........and

And also, we KNOW that in aqueous solution,

$pH+pOH=14$

$a.$ And thus, for $pOH=8.26$ , $[HO^-]=10^(-8.26)*mol*L^-1$

$=5xx10^-9*mol*L^-1$

And thus for $pH=5.74$ ,............................................

$[H_3O^+]=10^(-5.74)*mol*L^-1=1.82xx10^-6*mol*L^-1$ .

I will let you do $b.$ , and $c.$ . Post the values back in thread if you want them checked.

What is [H_3O^+][H_3O^+] in an aqueous solution whose pOH=8.26pOH=8.26?