Question #8632c

1 Answer
anor277
May 2, 2017

"Molarity"=0.10*mol*L^-1

Explanation:

By definition, "Molarity"="Moles of solute"/"Volume of solution (L)"..

And thus, here:

"Molarity"=((17.1*g)/(342.30*g*mol^-1))/(0.50*L)=0.10*mol*L^-1 with respect to sucrose.

So all I had to do was solve this quotient, and preserve the units of the quotient to give an answer in mol*L^-1............i.e. 1/(mol^-1)=1/(1/(mol))=mol as required...........

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